{"version":"1.0","provider_name":"Learning Center","provider_url":"https:\/\/www.eastcentral.edu\/learning-center","author_name":"dwalker","author_url":"https:\/\/www.eastcentral.edu\/learning-center\/author\/dwalker\/","title":"Solving for a Side Using Trig Ratios - Learning Center","type":"rich","width":600,"height":338,"html":"<blockquote class=\"wp-embedded-content\" data-secret=\"0rGZsMUUCa\"><a href=\"https:\/\/www.eastcentral.edu\/learning-center\/solving-for-a-side-using-trig-ratios\/\">Solving for a Side Using Trig Ratios<\/a><\/blockquote><iframe sandbox=\"allow-scripts\" security=\"restricted\" src=\"https:\/\/www.eastcentral.edu\/learning-center\/solving-for-a-side-using-trig-ratios\/embed\/#?secret=0rGZsMUUCa\" width=\"600\" height=\"338\" title=\"&#8220;Solving for a Side Using Trig Ratios&#8221; &#8212; Learning Center\" data-secret=\"0rGZsMUUCa\" frameborder=\"0\" marginwidth=\"0\" marginheight=\"0\" scrolling=\"no\" class=\"wp-embedded-content\"><\/iframe><script>\n\/*! This file is auto-generated *\/\n!function(d,l){\"use strict\";l.querySelector&&d.addEventListener&&\"undefined\"!=typeof URL&&(d.wp=d.wp||{},d.wp.receiveEmbedMessage||(d.wp.receiveEmbedMessage=function(e){var t=e.data;if((t||t.secret||t.message||t.value)&&!\/[^a-zA-Z0-9]\/.test(t.secret)){for(var s,r,n,a=l.querySelectorAll('iframe[data-secret=\"'+t.secret+'\"]'),o=l.querySelectorAll('blockquote[data-secret=\"'+t.secret+'\"]'),c=new RegExp(\"^https?:$\",\"i\"),i=0;i<o.length;i++)o[i].style.display=\"none\";for(i=0;i<a.length;i++)s=a[i],e.source===s.contentWindow&&(s.removeAttribute(\"style\"),\"height\"===t.message?(1e3<(r=parseInt(t.value,10))?r=1e3:~~r<200&&(r=200),s.height=r):\"link\"===t.message&&(r=new URL(s.getAttribute(\"src\")),n=new URL(t.value),c.test(n.protocol))&&n.host===r.host&&l.activeElement===s&&(d.top.location.href=t.value))}},d.addEventListener(\"message\",d.wp.receiveEmbedMessage,!1),l.addEventListener(\"DOMContentLoaded\",function(){for(var e,t,s=l.querySelectorAll(\"iframe.wp-embedded-content\"),r=0;r<s.length;r++)(t=(e=s[r]).getAttribute(\"data-secret\"))||(t=Math.random().toString(36).substring(2,12),e.src+=\"#?secret=\"+t,e.setAttribute(\"data-secret\",t)),e.contentWindow.postMessage({message:\"ready\",secret:t},\"*\")},!1)))}(window,document);\n\/\/# sourceURL=https:\/\/www.eastcentral.edu\/learning-center\/wp-includes\/js\/wp-embed.min.js\n<\/script>\n","description":"*Given an angle and a given side, one can solve for a missing side using trig ratios. The sides involved in this calculation are the opposite side (from angle A) and the hypotenuse. The trig ratio that relates the opposite side and hypotenuse is sine (opposite\/hypotenuse). Here is how the problem is set up: \u00a0\u00a0\u00a0\u00a0 [&hellip;]","thumbnail_url":"https:\/\/www.eastcentral.edu\/learning-center\/wp-content\/uploads\/sites\/27\/2026\/07\/right-triangle-2.png","thumbnail_width":421,"thumbnail_height":360}